freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-21-amicable-numbers.md

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---
id: 5900f3811000cf542c50fe94
title: 问题21友好的数字
challengeType: 5
videoUrl: ''
---
# --description--
设d `n` )定义为`n`的适当除数之`和` (小于`n的`数均匀分成`n` 。如果d `a` = `b`并且d `b` = `a` ,其中`a` ≠ `b` ,则`a`和`b`是友好对,并且`a`和`b`中的每`一个`被称为友好数字。例如220的适当除数是1,2,4,5,10,11,20,22,44,55和110;因此d220= 284. 284的适当除数是1,2,4,71和142;所以d284= 220.评估`n`下所有友好数字的总和。
# --hints--
`sumAmicableNum(1000)`应返回504。
```js
assert.strictEqual(sumAmicableNum(1000), 504);
```
`sumAmicableNum(2000)`应该返回2898。
```js
assert.strictEqual(sumAmicableNum(2000), 2898);
```
`sumAmicableNum(5000)`应该返回8442。
```js
assert.strictEqual(sumAmicableNum(5000), 8442);
```
`sumAmicableNum(10000)`应返回31626。
```js
assert.strictEqual(sumAmicableNum(10000), 31626);
```
# --solutions--