freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-413-one-child-numbe...

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---
id: 5900f50a1000cf542c51001c
title: 问题413独生子女号码
challengeType: 5
videoUrl: ''
---
# --description--
我们说如果其子串中的一个子串可被d整除则d位正数无前导零是一个子数。
例如5671是一个4位数的单子号码。在其所有子串5,6,7,1,56,67,71,567,671和5671中只有56可被4整除。类似地104是3位单子数因为只有0可被整除3. 1132451是一个7位数的单子号码因为只有245可被7整除。
设FN是小于N的一子数的数。我们可以验证F10= 9F103= 389和F107= 277674。
找到F1019
# --hints--
`euler413()`应该返回3079418648040719。
```js
assert.strictEqual(euler413(), 3079418648040719);
```
# --solutions--