freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/factorial.md

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---
id: 597b2b2a2702b44414742771
title: 阶乘
challengeType: 5
videoUrl: ''
---
# --description--
<p>编写一个函数来返回一个数字的阶乘。 </p><p>一个数字的因子由下式给出: </p> N = n \*n-1\*n-2\* ..... \* 1 <p>例如3 = 3 * 2 * 1 = 6 4 = 4 * 3 * 2 * 1 = 24 </p><p>注意0 = 1 </p>
# --hints--
`factorial`是一种功能。
```js
assert(typeof factorial === 'function');
```
`factorial(2)`应该返回一个数字。
```js
assert(typeof factorial(2) === 'number');
```
`factorial(3)`应该返回6.“)
```js
assert.equal(factorial(3), 6);
```
`factorial(3)`应返回120.“)
```js
assert.equal(factorial(5), 120);
```
`factorial(3)`应返回3,628,800。“
```js
assert.equal(factorial(10), 3628800);
```
# --solutions--