freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-an.../basic-algorithm-scripting/factorialize-a-number.chine...

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id title isRequired challengeType videoUrl localeTitle
a302f7aae1aa3152a5b413bc Factorialize a Number true 5 对一个数字进行推理

Description

返回提供的整数的阶乘。如果整数用字母n表示则阶乘是所有小于或等于n的正整数的乘积。因子通常用简写符号n!表示n!例如: 5! = 1 * 2 * 3 * 4 * 5 = 120只有大于或等于零的整数才会被提供给该函数。如果卡住,请记得使用Read-Search-Ask 。编写自己的代码。

Instructions

Tests

tests:
  - text: <code>factorialize(5)</code>应该返回一个数字。
    testString: 'assert(typeof factorialize(5) === "number", "<code>factorialize(5)</code> should return a number.");'
  - text: <code>factorialize(5)</code>应该返回120。
    testString: 'assert(factorialize(5) === 120, "<code>factorialize(5)</code> should return 120.");'
  - text: <code>factorialize(10)</code>应返回3628800。
    testString: 'assert(factorialize(10) === 3628800, "<code>factorialize(10)</code> should return 3628800.");'
  - text: <code>factorialize(20)</code>应该返回2432902008176640000。
    testString: 'assert(factorialize(20) === 2432902008176640000, "<code>factorialize(20)</code> should return 2432902008176640000.");'
  - text: <code>factorialize(0)</code>应该返回1。
    testString: 'assert(factorialize(0) === 1, "<code>factorialize(0)</code> should return 1.");'

Challenge Seed

function factorialize(num) {
  return num;
}

factorialize(5);

Solution

// solution required