freeCodeCamp

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id	challengeType	forumTopicId	title
587d7b8d367417b2b2512b5b	1	301233	学习函数式编程

Description

函数式编程是一种方案简单、功能独立、对作用域外没有任何副作用的编程范式。 INPUT -> PROCESS -> OUTPUT 函数式编程： 1）功能独立——不依赖于程序的状态（比如可能发生变化的全局变量）； 2）纯函数——同一个输入永远能得到同一个输出； 3）有限的副作用——可以严格地限制函数外部对状态的更改。

Instructions

freeCodeCamp 成员在 love tea 的故事。在代码编辑器中，已经为你定义好了prepareTea和getTea函数。调用getTea函数为团队准备 40 杯茶，并将它们存储在tea4TeamFCC变量里。

Tests

tests:
  - text: <code>tea4TeamFCC</code>变量里应有 40 杯为团队准备的茶。
    testString: assert(tea4TeamFCC.length === 40);
  - text: <code>tea4TeamFCC</code>变量里应有 greenTea。
    testString: assert(tea4TeamFCC[0] === 'greenTea');

Challenge Seed

/**
 * A long process to prepare tea.
 * @return {string} A cup of tea.
 **/
const prepareTea = () => 'greenTea';

/**
 * Get given number of cups of tea.
 * @param {number} numOfCups Number of required cups of tea.
 * @return {Array<string>} Given amount of tea cups.
 **/
const getTea = (numOfCups) => {
  const teaCups = [];

  for(let cups = 1; cups <= numOfCups; cups += 1) {
    const teaCup = prepareTea();
    teaCups.push(teaCup);
  }

  return teaCups;
};

// Add your code below this line

const tea4TeamFCC = null; // :(

// Add your code above this line

console.log(tea4TeamFCC);

Solution

// solution required
const prepareTea = () => 'greenTea';

const getTea = (numOfCups) => {
  const teaCups = [];
  
  for(let cups = 1; cups <= numOfCups; cups += 1) {
    const teaCup = prepareTea();
    teaCups.push(teaCup);
  }

  return teaCups;
};

const tea4TeamFCC = getTea(40);

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