freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-111-primes-with-run...

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---
id: 5900f3db1000cf542c50feee
challengeType: 5
videoUrl: ''
title: 问题111运行的Primes
---
## Description
<section id="description">考虑到包含重复数字的4位数素数很明显它们不能全部相同1111可被11整除2222可被22整除依此类推。但是有九个4位数的素数包含三个素数1117,1151,1171,1181,1511,1811,2111,4111,8111我们将说Mnd表示n-的最大重复数位数。数字素数其中d是重复数字Nnd表示这些素数的数量Snd表示这些素数的总和。所以M4,1= 3是4位数的素数的最大重复位数其中一个是重复的数字有N4,1= 9个这样的素数这些素数的总和是S 4,1= 22275.事实证明对于d = 0只能使M4,0= 2个重复数字但是存在N4,0= 13个这样的情况。同样地我们获得了4位素数的以下结果。 <p>数字d M4dN4dS4d0 2 13 67061 1 3 9 22275 2 3 1 2221 3 3 12 46214 4 3 2 8888 5 3 1 5557 6 3 1 6661 7 3 9 57863 8 3 1 8887 9 3 7 48073 </p><p>对于d = 0到9所有S4d的总和是273700.求所有S10d的总和。 </p></section>
## Instructions
<section id="instructions">
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: <code>euler111()</code>应返回612407567715。
testString: assert.strictEqual(euler111(), 612407567715);
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
function euler111() {
// Good luck!
return true;
}
euler111();
```
</div>
</section>
## Solution
<section id='solution'>
```js
// solution required
```
/section>