56 lines
984 B
Markdown
56 lines
984 B
Markdown
---
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id: 5900f4291000cf542c50ff3b
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challengeType: 5
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videoUrl: ''
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title: 问题188：数字的过度扩展
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---
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## Description
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<section id="description">由↑^ b或ba表示的正整数b的数字a的过度增强或分解通过以下方式递归地定义：a↑↑1 = a，a↑↑（k + 1）= a（a↑↑k ）。 <p>因此我们有例如3↑↑2 = 33 = 27，因此3↑↑3 = 327 = 7625597484987和3↑↑4大致是103.6383346400240996 * 10 ^ 12。查找1777↑↑1855的最后8位数字。 </p></section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>euler188()</code>应该返回95962097。
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testString: assert.strictEqual(euler188(), 95962097);
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function euler188() {
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// Good luck!
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return true;
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}
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euler188();
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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/section>
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