freeCodeCamp/curriculum/challenges/chinese/03-front-end-libraries/redux/remove-an-item-from-an-arra...

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id title challengeType isRequired videoUrl localeTitle
5a24c314108439a4d403615a Remove an Item from an Array 6 false 从数组中删除项目

Description

是时候练习从数组中删除项目了。扩展运算符也可以在这里使用。其他有用的JavaScript方法包括slice()concat()

Instructions

修改了reducer和action creator以根据项目的索引从数组中删除项目。完成编写reducer以便返回一个新的状态数组并删除特定索引处的项。

Tests

tests:
  - text: 'Redux存储应该存在并初始化为等于<code>[0,1,2,3,4,5]</code>的状态'
    testString: 'assert((function() { const initialState = store.getState(); return (Array.isArray(initialState) === true && DeepEqual(initialState, [0, 1, 2, 3, 4, 5])); })(), "The Redux store should exist and initialize with a state equal to <code>[0,1,2,3,4,5]</code>");'
  - text: <code>removeItem</code>和<code>immutableReducer</code>都应该是函数。
    testString: 'assert(typeof removeItem === "function" && typeof immutableReducer === "function", "<code>removeItem</code> and <code>immutableReducer</code> both should be functions.");'
  - text: 调度<code>removeItem</code>动作创建者应该从状态中删除项目,不应该改变状态。
    testString: 'assert((function() { const initialState = store.getState(); const isFrozen = DeepFreeze(initialState); store.dispatch(removeItem(3)); const state_1 = store.getState(); store.dispatch(removeItem(2)); const state_2 = store.getState(); store.dispatch(removeItem(0)); store.dispatch(removeItem(0)); store.dispatch(removeItem(0)); const state_3 = store.getState(); return isFrozen && DeepEqual(state_1, [0, 1, 2, 4, 5]) && DeepEqual(state_2, [0, 1, 4, 5]) && DeepEqual(state_3, [5]); })(), "Dispatching the <code>removeItem</code> action creator should remove items from the state and should NOT mutate state.");'

Challenge Seed

const immutableReducer = (state = [0,1,2,3,4,5], action) => {
  switch(action.type) {
    case 'REMOVE_ITEM':
      // don't mutate state here or the tests will fail
      return
    default:
      return state;
  }
};

const removeItem = (index) => {
  return {
    type: 'REMOVE_ITEM',
    index
  }
}

const store = Redux.createStore(immutableReducer);

Solution

// solution required