1.6 KiB
1.6 KiB
id | challengeType | title | videoUrl | localeTitle |
---|---|---|---|---|
5900f3721000cf542c50fe85 | 5 | Problem 6: Sum square difference | 问题6:求和方差 |
Description
1 2 + 2 2 + ... + 10 2 = 385
前十个自然数之和的平方是, (1 + 2 + ... + 10) 2 = 55 2 = 3025
因此,前十个自然数的平方和与和的平方之间的差值为3025 - 385 = 2640.求出前n
自然数的平方和与总和的平方之间的差值。 Instructions
Tests
tests:
- text: <code>sumSquareDifference(10)</code>应该返回2640。
testString: 'assert.strictEqual(sumSquareDifference(10), 2640, "<code>sumSquareDifference(10)</code> should return 2640.");'
- text: <code>sumSquareDifference(20)</code>应该返回41230。
testString: 'assert.strictEqual(sumSquareDifference(20), 41230, "<code>sumSquareDifference(20)</code> should return 41230.");'
- text: <code>sumSquareDifference(100)</code>应该返回25164150。
testString: 'assert.strictEqual(sumSquareDifference(100), 25164150, "<code>sumSquareDifference(100)</code> should return 25164150.");'
Challenge Seed
function sumSquareDifference(n) {
// Good luck!
return true;
}
sumSquareDifference(100);
Solution
// solution required