2.0 KiB
2.0 KiB
title | id | challengeType | videoUrl | localeTitle |
---|---|---|---|---|
Day of the week | 5966f99c45e8976909a85575 | 5 | 一周中的天 |
Description
一家公司决定,每当圣诞节落在星期天,他们将给予他们的工人所有额外带薪假期,这样,在任何公共假期,工人将不必在下一周(12月25日到1月1日之间)工作。
任务:
编写一个开始年份和结束年份的函数,并返回12月25日为星期日的所有年份的数组。
Instructions
Tests
tests:
- text: <code>findXmasSunday</code>是一个函数。
testString: 'assert(typeof findXmasSunday === "function", "<code>findXmasSunday</code> is a function.");'
- text: '<code>findChristmasSunday(2000, 2100)</code>应该返回一个数组。'
testString: 'assert(typeof findXmasSunday(2000, 2100) === "object", "<code>findChristmasSunday(2000, 2100)</code> should return an array.");'
- text: '<code>findChristmasSunday(2008, 2121</code>应该回归[1977,1983,1988,1994,2005,2011,2016]'
testString: 'assert.deepEqual(findXmasSunday(1970, 2017), firstSolution, "<code>findChristmasSunday(2008, 2121</code> should return [1977, 1983, 1988, 1994, 2005, 2011, 2016]");'
- text: '<code>findChristmasSunday(2008, 2121</code>应该返回[2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118]'
testString: 'assert.deepEqual(findXmasSunday(2008, 2121), secondSolution, "<code>findChristmasSunday(2008, 2121</code> should return [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]");'
Challenge Seed
function findXmasSunday (start, end) {
// Good luck!
return true;
}
After Test
console.info('after the test');
Solution
// solution required