freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/spiral-matrix.md

1.8 KiB

id title challengeType forumTopicId dashedName
5a23c84252665b21eecc801c Spiral matrix 5 302321 spiral-matrix

--description--

Produce a spiral array. A spiral array is a square arrangement of the first N2 natural numbers, where the numbers increase sequentially as you go around the edges of the array spiraling inwards. For example, given 5, produce this array:

0  1  2  3  4
15 16 17 18 5
14 23 24 19 6
13 22 21 20 7
12 11 10  9 8

--hints--

spiralArray should be a function.

assert(typeof spiralArray == 'function');

spiralArray(3) should return an array.

assert(Array.isArray(spiralArray(3)));

spiralArray(3) should return [[0, 1, 2],[7, 8, 3],[6, 5, 4]].

assert.deepEqual(spiralArray(3), [
  [0, 1, 2],
  [7, 8, 3],
  [6, 5, 4]
]);

spiralArray(4) should return [[0, 1, 2, 3],[11, 12, 13, 4],[10, 15, 14, 5],[9, 8, 7, 6]].

assert.deepEqual(spiralArray(4), [
  [0, 1, 2, 3],
  [11, 12, 13, 4],
  [10, 15, 14, 5],
  [9, 8, 7, 6]
]);

spiralArray(5) should return [[0, 1, 2, 3, 4],[15, 16, 17, 18, 5],[14, 23, 24, 19, 6],[13, 22, 21, 20, 7],[12, 11, 10, 9, 8]].

assert.deepEqual(spiralArray(5), [
  [0, 1, 2, 3, 4],
  [15, 16, 17, 18, 5],
  [14, 23, 24, 19, 6],
  [13, 22, 21, 20, 7],
  [12, 11, 10, 9, 8]
]);

--seed--

--seed-contents--

function spiralArray(n) {

}

--solutions--

function spiralArray(n) {
  var arr = Array(n),
    x = 0,
    y = n,
    total = n * n--,
    dx = 1,
    dy = 0,
    i = 0,
    j = 0;
  while (y) arr[--y] = [];
  while (i < total) {
    arr[y][x] = i++;
    x += dx;
    y += dy;
    if (++j == n) {
      if (dy < 0) {
        x++;
        y++;
        n -= 2;
      }
      j = dx;
      dx = -dy;
      dy = j;
      j = 0;
    }
  }
  return arr;
}