freeCodeCamp/curriculum/challenges/chinese/08-coding-interview-prep/rosetta-code/day-of-the-week.chinese.md

title	id	challengeType	videoUrl	localeTitle
Day of the week	5966f99c45e8976909a85575	5		一周中的天

Description

一家公司决定，每当圣诞节落在星期天，他们将给予他们的工人所有额外带薪假期，这样，在任何公共假期，工人将不必在下一周（12月25日到1月1日之间）工作。

任务：

编写一个开始年份和结束年份的函数，并返回12月25日为星期日的所有年份的数组。

Instructions

Tests

tests:
  - text: <code>findXmasSunday</code>是一个函数。
    testString: 'assert(typeof findXmasSunday === "function", "<code>findXmasSunday</code> is a function.");'
  - text: '<code>findChristmasSunday(2000, 2100)</code>应该返回一个数组。'
    testString: 'assert(typeof findXmasSunday(2000, 2100) === "object", "<code>findChristmasSunday(2000, 2100)</code> should return an array.");'
  - text: '<code>findChristmasSunday(2008, 2121</code>应该回归[1977,1983,1988,1994,2005,2011,2016]'
    testString: 'assert.deepEqual(findXmasSunday(1970, 2017), firstSolution, "<code>findChristmasSunday(2008, 2121</code> should return [1977, 1983, 1988, 1994, 2005, 2011, 2016]");'
  - text: '<code>findChristmasSunday(2008, 2121</code>应该返回[2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118]'
    testString: 'assert.deepEqual(findXmasSunday(2008, 2121), secondSolution, "<code>findChristmasSunday(2008, 2121</code> should return [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]");'

Challenge Seed

function findXmasSunday (start, end) {
  // Good luck!
  return true;
}

After Test

console.info('after the test');

Solution

// solution required