5.8 KiB
5.8 KiB
id | title | challengeType | videoUrl | localeTitle |
---|---|---|---|---|
587d8254367417b2b2512c6f | Perform a Subset Check on Two Sets of Data | 1 | Выполните проверку подмножества на двух наборах данных |
Description
Set
структуры данных называется subset
. Это будет сравнивать первый набор, второй и если первый набор полностью содержится внутри второго, тогда он вернет true. Например, если setA = ['a','b']
и setB = ['a','b','c','d']
, то подмножество setA и setB будет: setA.subset(setB)
должно быть true
. Instructions
Tests
tests:
- text: Класс <code>Set</code> должен иметь метод <code>union</code> .
testString: 'assert(function(){var test = new Set(); return (typeof test.subset === "function")}, "Your <code>Set</code> class should have a <code>union</code> method.");'
- text: Первый Set () содержался во втором наборе
testString: 'assert(function(){var setA = new Set(); var setB = new Set(); setA.add("a"); setB.add("b"); setB.add("c"); setB.add("a"); setB.add("d"); var subsetSetAB = setA.subset(setB);return (subsetSetAB === true)}, "The first Set() was contained in the second Set");'
- text: '<code>["a", "b"].subset(["a", "b", "c", "d"])</code> должно возвращать <code>true</code> ").'
testString: 'assert(function(){var setA = new Set(); var setB = new Set(); setA.add("a"); setA.add("b"); setB.add("a"); setB.add("b"); setB.add("c"); setB.add("d"); var subsetSetAB = setA.subset(setB); return (subsetSetAB === true)}, "<code>["a", "b"].subset(["a", "b", "c", "d"])</code> should return <code>true</code>");'
- text: '<code>["a", "b", "c"].subset(["a", "b"])</code> должно возвращать <code>false</code> ").'
testString: 'assert(function(){var setA = new Set(); var setB = new Set(); setA.add("a"); setA.add("b"); setA.add("c"); setB.add("a"); setB.add("b"); var subsetSetAB = setA.subset(setB); return (subsetSetAB === false)}, "<code>["a", "b", "c"].subset(["a", "b"])</code> should return <code>false</code>");'
- text: '<code>[].subset([])</code> должен возвращать <code>true</code>'
testString: 'assert(function(){var setA = new Set(); var setB = new Set(); var subsetSetAB = setA.subset(setB); return (subsetSetAB === true)}, "<code>[].subset([])</code> should return <code>true</code>");'
- text: '<code>["a", "b"].subset(["c", "d"])</code> должно возвращать <code>false</code> ").'
testString: 'assert(function(){var setA = new Set(); var setB = new Set(); setA.add("a"); setA.add("b"); setB.add("c"); setB.add("d"); var subsetSetAB = setA.subset(setB); return (subsetSetAB === false)}, "<code>["a", "b"].subset(["c", "d"])</code> should return <code>false</code>");'
Challenge Seed
function Set() {
// the var collection will hold the set
var collection = [];
// this method will check for the presence of an element and return true or false
this.has = function(element) {
return (collection.indexOf(element) !== -1);
};
// this method will return all the values in the set
this.values = function() {
return collection;
};
// this method will add an element to the set
this.add = function(element) {
if(!this.has(element)){
collection.push(element);
return true;
}
return false;
};
// this method will remove an element from a set
this.remove = function(element) {
if(this.has(element)){
var index = collection.indexOf(element);
collection.splice(index,1);
return true;
}
return false;
};
// this method will return the size of the collection
this.size = function() {
return collection.length;
};
// this method will return the union of two sets
this.union = function(otherSet) {
var unionSet = new Set();
var firstSet = this.values();
var secondSet = otherSet.values();
firstSet.forEach(function(e){
unionSet.add(e);
});
secondSet.forEach(function(e){
unionSet.add(e);
});
return unionSet;
};
// this method will return the intersection of two sets as a new set
this.intersection = function(otherSet) {
var intersectionSet = new Set();
var firstSet = this.values();
firstSet.forEach(function(e){
if(otherSet.has(e)){
intersectionSet.add(e);
}
});
return intersectionSet;
};
// this method will return the difference of two sets as a new set
this.difference = function(otherSet) {
var differenceSet = new Set();
var firstSet = this.values();
firstSet.forEach(function(e){
if(!otherSet.has(e)){
differenceSet.add(e);
}
});
return differenceSet;
};
// change code below this line
// change code above this line
}
Solution
// solution required