freeCodeCamp/curriculum/challenges/english/08-coding-interview-prep/rosetta-code/spiral-matrix.english.md

2.6 KiB

id title challengeType forumTopicId
5a23c84252665b21eecc801c Spiral matrix 5 302321

Description

Produce a spiral array. A spiral array is a square arrangement of the first N2 natural numbers, where the numbers increase sequentially as you go around the edges of the array spiraling inwards. For example, given 5, produce this array:

0  1  2  3  4
15 16 17 18 5
14 23 24 19 6
13 22 21 20 7
12 11 10  9 8

Instructions

Tests

tests:
  - text: <code>spiralArray</code> should be a function.
    testString: assert(typeof spiralArray=='function','<code>spiralArray</code> should be a function.');
  - text: <code>spiralArray(3)</code> should return an array.
    testString: assert(Array.isArray(spiralArray(3)), '<code>spiralArray(3)</code> should return an array.');
  - text: <code>spiralArray(3)</code> should return <code>[[0, 1, 2],[7, 8, 3],[6, 5, 4]]</code>.
    testString: assert.deepEqual(spiralArray(3), [[0, 1, 2], [7, 8, 3], [6, 5, 4]], '<code>spiralArray(3)</code> should return <code>[[0, 1, 2],[7, 8, 3],[6, 5, 4]]</code>.');
  - text: <code>spiralArray(4)</code> should return <code>[[0, 1, 2, 3],[11, 12, 13, 4],[10, 15, 14, 5],[9, 8, 7, 6]]</code>.
    testString: assert.deepEqual(spiralArray(4), [[0, 1, 2, 3], [11, 12, 13, 4], [10, 15, 14, 5], [9, 8, 7, 6]], '<code>spiralArray(4)</code> should return <code>[[0, 1, 2, 3],[11, 12, 13, 4],[10, 15, 14, 5],[9, 8, 7, 6]]</code>.');
  - text: <code>spiralArray(5)</code> should return <code>[[0, 1, 2, 3, 4],[15, 16, 17, 18, 5],[14, 23, 24, 19, 6],[13, 22, 21, 20, 7],[12, 11, 10, 9, 8]]</code>.
    testString: assert.deepEqual(spiralArray(5), [[0, 1, 2, 3, 4], [15, 16, 17, 18, 5], [14, 23, 24, 19, 6], [13, 22, 21, 20, 7], [12, 11, 10, 9, 8]], '<code>spiralArray(5)</code> should return <code>[[0, 1, 2, 3, 4],[15, 16, 17, 18, 5],[14, 23, 24, 19, 6],[13, 22, 21, 20, 7],[12, 11, 10, 9, 8]]</code>.');

Challenge Seed

function spiralArray(n) {
  // Good luck!
}

Solution

function spiralArray(n) {
    var arr = Array(n),
        x = 0, y = n,
        total = n * n--,
        dx = 1, dy = 0,
        i = 0, j = 0;
    while (y) arr[--y] = [];
    while (i < total) {
        arr[y][x] = i++;
        x += dx; y += dy;
        if (++j == n) {
            if (dy < 0) {x++; y++; n -= 2}
            j = dx; dx = -dy; dy = j; j = 0;
       }
    }
    return arr;
}