freeCodeCamp/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-156-counting-digits.md

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---
id: 5900f4091000cf542c50ff1b
title: 'Problem 156: Counting Digits'
challengeType: 5
forumTopicId: 301787
dashedName: problem-156-counting-digits
---
# --description--
Starting from zero the natural numbers are written down in base 10 like this:
0 1 2 3 4 5 6 7 8 9 10 11 12....
Consider the digit $d = 1$. After we write down each number n, we will update the number of ones that have occurred and call this number $f(n, 1)$. The first values for $f(n, 1)$, then, are as follows:
| $n$ | $f(n, 1)$ |
|-----|-----------|
| 0 | 0 |
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 1 |
| 5 | 1 |
| 6 | 1 |
| 7 | 1 |
| 8 | 1 |
| 9 | 1 |
| 10 | 2 |
| 11 | 4 |
| 12 | 5 |
Note that $f(n, 1)$ never equals 3.
So the first two solutions of the equation $f(n, 1) = n$ are $n = 0$ and $n = 1$. The next solution is $n = 199981$. In the same manner the function $f(n, d)$ gives the total number of digits d that have been written down after the number $n$ has been written.
In fact, for every digit $d ≠ 0$, 0 is the first solution of the equation $f(n, d) = n$. Let $s(d)$ be the sum of all the solutions for which $f(n, d) = n$.
You are given that $s(1) = 22786974071$. Find $\sum{s(d)}$ for $1 ≤ d ≤ 9$.
Note: if, for some $n$, $f(n, d) = n$ for more than one value of $d$ this value of $n$ is counted again for every value of $d$ for which $f(n, d) = n$.
# --hints--
`countingDigits()` should return `21295121502550`.
```js
assert.strictEqual(countingDigits(), 21295121502550);
```
# --seed--
## --seed-contents--
```js
function countingDigits() {
return true;
}
countingDigits();
```
# --solutions--
```js
// solution required
```