1.6 KiB
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
5900f4241000cf542c50ff37 | Problem 184: Triangles containing the origin | 5 | 301820 | problem-184-triangles-containing-the-origin |
--description--
Consider the set I_r
of points (x,y)
with integer coordinates in the interior of the circle with radius r
, centered at the origin, i.e. x^2 + y^2 < r^2
.
For a radius of 2, I_2
contains the nine points (0,0), (1,0), (1,1), (0,1), (-1,1), (-1,0), (-1,-1), (0,-1) and (1,-1). There are eight triangles having all three vertices in I_2
which contain the origin in the interior. Two of them are shown below, the others are obtained from these by rotation.
For a radius of 3, there are 360 triangles containing the origin in the interior and having all vertices in I_3
and for I_5
the number is 10600.
How many triangles are there containing the origin in the interior and having all three vertices in I_{105}
?
--hints--
trianglesConttainingOrigin()
should return 1725323624056
.
assert.strictEqual(trianglesConttainingOrigin(), 1725323624056);
--seed--
--seed-contents--
function trianglesContainingOrigin() {
return true;
}
trianglesContainingOrigin();
--solutions--
// solution required