freeCodeCamp/curriculum/challenges/english/08-coding-interview-prep/data-structures/perform-an-intersection-on-...

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---
id: 587d8253367417b2b2512c6d
title: Perform an Intersection on Two Sets of Data
challengeType: 1
---
## Description
<section id='description'>
In this exercise we are going to perform an intersection on 2 sets of data. We will create a method on our <code>Set</code> data structure called <code>intersection</code>. An intersection of sets represents all values that are common to two or more sets. This method should take another <code>Set</code> as an argument and return the <code>intersection</code> of the two sets.
For example, if <code>setA = ['a','b','c']</code> and <code>setB = ['a','b','d','e']</code>, then the intersection of setA and setB is: <code>setA.intersection(setB) = ['a', 'b']</code>.
</section>
## Instructions
<section id='instructions'>
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: Your <code>Set</code> class should have a <code>intersection</code> method.
testString: assert((function(){var test = new Set(); return (typeof test.intersection === 'function')})(), 'Your <code>Set</code> class should have a <code>intersection</code> method.');
- text: The proper collection was returned
testString: assert((function(){ var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('c'); setB.add('d'); var intersectionSetAB = setA.intersection(setB); return (intersectionSetAB.size() === 1 && intersectionSetAB.values()[0] === 'c')})(), 'The proper collection was returned');
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
function Set() {
// the var collection will hold the set
var collection = [];
// this method will check for the presence of an element and return true or false
this.has = function(element) {
return (collection.indexOf(element) !== -1);
};
// this method will return all the values in the set
this.values = function() {
return collection;
};
// this method will add an element to the set
this.add = function(element) {
if(!this.has(element)){
collection.push(element);
return true;
}
return false;
};
// this method will remove an element from a set
this.remove = function(element) {
if(this.has(element)){
var index = collection.indexOf(element);
collection.splice(index,1);
return true;
}
return false;
};
// this method will return the size of the collection
this.size = function() {
return collection.length;
};
// this method will return the union of two sets
this.union = function(otherSet) {
var unionSet = new Set();
var firstSet = this.values();
var secondSet = otherSet.values();
firstSet.forEach(function(e){
unionSet.add(e);
});
secondSet.forEach(function(e){
unionSet.add(e);
});
return unionSet;
};
// change code below this line
// change code above this line
}
```
</div>
</section>
## Solution
<section id='solution'>
```js
function Set() {
// the var collection will hold the set
var collection = [];
// this method will check for the presence of an element and return true or false
this.has = function(element) {
return (collection.indexOf(element) !== -1);
};
// this method will return all the values in the set
this.values = function() {
return collection;
};
// this method will add an element to the set
this.add = function(element) {
if(!this.has(element)){
collection.push(element);
return true;
}
return false;
};
// this method will remove an element from a set
this.remove = function(element) {
if(this.has(element)){
var index = collection.indexOf(element);
collection.splice(index,1);
return true;
}
return false;
};
// this method will return the size of the collection
this.size = function() {
return collection.length;
};
// this method will return the union of two sets
this.union = function(otherSet) {
var unionSet = new Set();
var firstSet = this.values();
var secondSet = otherSet.values();
firstSet.forEach(function(e){
unionSet.add(e);
});
secondSet.forEach(function(e){
unionSet.add(e);
});
return unionSet;
};
this.intersection = function(otherSet) {
var intersectionSet = new Set();
var firstSet = this.values();
firstSet.forEach(function(e) {
if (otherSet.has(e)) {
intersectionSet.add(e);
}
})
return intersectionSet;
}
}
```
</section>