1.0 KiB
1.0 KiB
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Smallest multiple |
Problem 5: Smallest multiple
Method:
- In this challenge we need to find the LCM of 1 to n numbers.
- To find LCM of a number we use the following formula:
- To find GCD (Greatest Common Divisor) of two number we use Euclidean algorithm.
- Once we get LCM of two numbers, we can get LCM of the numbers from 1 to n.
Solution:
//LCM of two numbers
function lcm(a, b){
return (a*b)/gcd(a, b);
}
//Euclidean recursive algorithm
function gcd(a, b){
if (b === 0) return a;
return gcd(b, a%b);
}
function smallestMult(n){
let maxLCM = 1;
//Getting the LCM in the range
for (let i = 2; i <= n; i++){
maxLCM = lcm(maxLCM, i);
}
return maxLCM;
}