1.1 KiB
1.1 KiB
title |
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Use Caution When Reinitializing Variables Inside a Loop |
Use Caution When Reinitializing Variables Inside a Loop
- This challenge must be solved by redefining the scope of
row[]
. - Below is an example of the desired matrix.
[
[0][0],
[0][0],
[0][0]
]
- However the current matrix - seen below - is far from the desired matrix
[
[0][0][0][0][0][0],
[0][0][0][0][0][0],
[0][0][0][0][0][0]
]
- This error occurs due to the
row[]
array being declared as a global variable outside of the nested for loop. - However, to fill the matrix correctly the
row[]
array must be reset after each iteration of the outer loop.
Solution
function zeroArray(m, n) {
let newArray = [];
for (let i = 0; i < m; i++) {
let row = []; /* <----- row has been declared inside the outer loop.
Now a new row will be initialised during each iteration of the outer loop allowing
for the desired matrix. */
for (let j = 0; j < n; j++) {
row.push(0);
}
newArray.push(row);
}
return newArray;
}
let matrix = zeroArray(3, 2);
console.log(matrix);