45 lines
898 B
Markdown
45 lines
898 B
Markdown
---
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id: 5900f4291000cf542c50ff3b
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title: 'Problem 188: The hyperexponentiation of a number'
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challengeType: 5
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forumTopicId: 301824
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dashedName: problem-188-the-hyperexponentiation-of-a-number
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---
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# --description--
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The hyperexponentiation or tetration of a number $a$ by a positive integer $b$, denoted by $a↑↑b$ or ${}^ba$, is recursively defined by:
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$a↑↑1 = a$,
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$a↑↑(k+1) = a^{(a↑↑k)}$.
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Thus we have e.g. $3↑↑2 = 3^3 = 27$, hence $3↑↑3 = 3^{27} = 7625597484987$ and $3↑↑4$ is roughly ${10}^{3.6383346400240996 \times {10}^{12}}$. Find the last 8 digits of $1777↑↑1855$.
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# --hints--
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`hyperexponentation()` should return `95962097`.
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```js
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assert.strictEqual(hyperexponentation(), 95962097);
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```
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# --seed--
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## --seed-contents--
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```js
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function hyperexponentation() {
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return true;
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}
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hyperexponentation();
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```
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# --solutions--
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```js
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// solution required
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```
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