freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-58-spiral-primes.md

1.7 KiB

id title challengeType forumTopicId dashedName
5900f3a61000cf542c50feb9 Problem 58: Spiral primes 5 302169 problem-58-spiral-primes

--description--

Starting with 1 and spiralling anticlockwise in the following way, a square spiral with side length 7 is formed.

37 36 35 34 33 32 31
38 17 16 15 14 13 30
39 18  5  4  3 12 29
40 19  6  1  2 11 28
41 20  7  8  9 10 27
42 21 22 23 24 25 26
43 44 45 46 47 48 49

It is interesting to note that the odd squares lie along the bottom right diagonal, but what is more interesting is that 8 out of the 13 numbers lying along both diagonals are prime; that is, a ratio of 8/13 ≈ 62%.

If one complete new layer is wrapped around the spiral above, a square spiral with side length 9 will be formed. If this process is continued, what is the side length of the square spiral for which the ratio of primes along both diagonals first falls below 10%?

--hints--

spiralPrimes() should return a number.

assert(typeof spiralPrimes() === 'number');

spiralPrimes() should return 26241.

assert.strictEqual(spiralPrimes(), 26241);

--seed--

--seed-contents--

function spiralPrimes() {

  return true;
}

spiralPrimes();

--solutions--

// solution required