freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-69-totient-maximum.md

2.0 KiB

id title challengeType forumTopicId dashedName
5900f3b11000cf542c50fec4 Problem 69: Totient maximum 5 302181 problem-69-totient-maximum

--description--

Euler's Totient function, φ(n) [sometimes called the phi function], is used to determine the number of numbers less than n which are relatively prime to n. For example, as 1, 2, 4, 5, 7, and 8, are all less than nine and relatively prime to nine, φ(9)=6.

!!crwdBlockTags_15_sgaTkcolBdwrc!! Relatively Prime φ(!!crwdBlockTags_16_sgaTkcolBdwrc!!) !!crwdBlockTags_17_sgaTkcolBdwrc!!/φ(!!crwdBlockTags_18_sgaTkcolBdwrc!!)
2 1 1 2
3 1,2 2 1.5
4 1,3 2 2
5 1,2,3,4 4 1.25
6 1,5 2 3
7 1,2,3,4,5,6 6 1.1666...
8 1,3,5,7 4 2
9 1,2,4,5,7,8 6 1.5
10 1,3,7,9 4 2.5

It can be seen that n=6 produces a maximum n/φ(n) for n ≤ 10.

Find the value of n ≤ 1,000,000 for which n/φ(n) is a maximum.

--hints--

totientMaximum() should return a number.

assert(typeof totientMaximum() === 'number');

totientMaximum() should return 510510.

assert.strictEqual(totientMaximum(), 510510);

--seed--

--seed-contents--

function totientMaximum() {

  return true;
}

totientMaximum();

--solutions--

// solution required