freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/smallest-common-multiple.chinese.md

id	title	isRequired	challengeType	videoUrl	localeTitle
ae9defd7acaf69703ab432ea	Smallest Common Multiple	true	5		最小的共同多重

Description

找到所提供参数的最小公倍数，可以均匀地除以这些参数，以及这些参数之间范围内的所有序号。范围将是两个数字的数组，不一定按数字顺序排列。例如，如果给定1和3，找到1和3的最小公倍数，它们也可以被1到3 之间的所有数字整除。这里的答案是6.记得使用Read-Search-Ask如果你得到卡住。尝试配对程序。编写自己的代码。

Instructions

Tests

tests:
  - text: '<code>smallestCommons([1, 5])</code>应返回一个数字。'
    testString: 'assert.deepEqual(typeof smallestCommons([1, 5]), "number", "<code>smallestCommons([1, 5])</code> should return a number.");'
  - text: '<code>smallestCommons([1, 5])</code>应该返回60。'
    testString: 'assert.deepEqual(smallestCommons([1, 5]), 60, "<code>smallestCommons([1, 5])</code> should return 60.");'
  - text: '<code>smallestCommons([5, 1])</code>应该返回60。'
    testString: 'assert.deepEqual(smallestCommons([5, 1]), 60, "<code>smallestCommons([5, 1])</code> should return 60.");'
  - text: '<code>smallestCommons([2, 10])</code> 2,10 <code>smallestCommons([2, 10])</code>应返回2520。'
    testString: 'assert.deepEqual(smallestCommons([2, 10]), 2520, "<code>smallestCommons([2, 10])</code> should return 2520.");'
  - text: '<code>smallestCommons([1, 13])</code> 1,13 <code>smallestCommons([1, 13])</code>应返回360360。'
    testString: 'assert.deepEqual(smallestCommons([1, 13]), 360360, "<code>smallestCommons([1, 13])</code> should return 360360.");'
  - text: '<code>smallestCommons([23, 18])</code> 23,18 <code>smallestCommons([23, 18])</code>应返回6056820。'
    testString: 'assert.deepEqual(smallestCommons([23, 18]), 6056820, "<code>smallestCommons([23, 18])</code> should return 6056820.");'

Challenge Seed

function smallestCommons(arr) {
  return arr;
}


smallestCommons([1,5]);

Solution

// solution required