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id	challengeType	title	forumTopicId
5900f4fd1000cf542c51000f	5	Problem 401: Sum of squares of divisors	302069

Description

The divisors of 6 are 1,2,3 and 6. The sum of the squares of these numbers is 1+4+9+36=50.

Let sigma2(n) represent the sum of the squares of the divisors of n. Thus sigma2(6)=50.

Let SIGMA2 represent the summatory function of sigma2, that is SIGMA2(n)=∑sigma2(i) for i=1 to n. The first 6 values of SIGMA2 are: 1,6,16,37,63 and 113.

Find SIGMA2(1015) modulo 109.

Instructions

Tests

tests:
  - text: <code>euler401()</code> should return 281632621.
    testString: assert.strictEqual(euler401(), 281632621);

Challenge Seed

function euler401() {
  // Good luck!
  return true;
}

euler401();

Solution

// solution required

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