freeCodeCamp/curriculum/challenges/english/08-coding-interview-prep/project-euler/problem-65-convergents-of-e...

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---
id: 5900f3ad1000cf542c50fec0
challengeType: 5
title: 'Problem 65: Convergents of e'
forumTopicId: 302177
---
## Description
<section id='description'>
The square root of 2 can be written as an infinite continued fraction.
√2 = 1 +
1
2 +
1
2 +
1
2 +
1
2 + ...
The infinite continued fraction can be written, √2 = [1;(2)], (2) indicates that 2 repeats ad infinitum. In a similar way, √23 = [4;(1,3,1,8)].
It turns out that the sequence of partial values of continued fractions for square roots provide the best rational approximations. Let us consider the convergents for √2.
1 +
1
= 3/2
2
1 +
1
= 7/5
2 +
1
2
1 +
1
= 17/12
2 +
1
2 +
1
2
1 +
1
= 41/29
2 +
1
2 +
1
2 +
1
2
Hence the sequence of the first ten convergents for √2 are:
1, 3/2, 7/5, 17/12, 41/29, 99/70, 239/169, 577/408, 1393/985, 3363/2378, ...
What is most surprising is that the important mathematical constant,e = [2; 1,2,1, 1,4,1, 1,6,1 , ... , 1,2k,1, ...].
The first ten terms in the sequence of convergents for e are:
2, 3, 8/3, 11/4, 19/7, 87/32, 106/39, 193/71, 1264/465, 1457/536, ...
The sum of digits in the numerator of the 10th convergent is 1+4+5+7=17.
Find the sum of digits in the numerator of the 100th convergent of the continued fraction for e.
</section>
## Instructions
<section id='instructions'>
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: <code>euler65()</code> should return 272.
testString: assert.strictEqual(euler65(), 272);
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
function euler65() {
// Good luck!
return true;
}
euler65();
```
</div>
</section>
## Solution
<section id='solution'>
```js
// solution required
```
</section>