freeCodeCamp/curriculum/challenges/chinese/08-coding-interview-prep/project-euler/problem-1-multiples-of-3-and-5.chinese.md

id	challengeType	title	videoUrl	localeTitle
5900f36e1000cf542c50fe80	5	Problem 1: Multiples of 3 and 5		问题1：3和5的倍数

Description

如果我们列出10以下是3或5的倍数的所有自然数，我们得到3,5,6和9.这些倍数的总和是23.求出所提供参数以下3或5的所有倍数的总和价值number 。

Instructions

Tests

tests:
  - text: <code>multiplesOf3and5(1000)</code>应该返回233168。
    testString: 'assert.strictEqual(multiplesOf3and5(1000), 233168, "<code>multiplesOf3and5(1000)</code> should return 233168.");'
  - text: <code>multiplesOf3and5(49)</code>应该返回543。
    testString: 'assert.strictEqual(multiplesOf3and5(49), 543, "<code>multiplesOf3and5(49)</code> should return 543.");'
  - text: <code>multiplesOf3and5(19564)</code>应该返回89301183。
    testString: 'assert.strictEqual(multiplesOf3and5(19564), 89301183, "<code>multiplesOf3and5(19564)</code> should return 89301183.");'
  - text: 您的函数未使用我们的测试值返回正确的结果。
    testString: 'assert.strictEqual(multiplesOf3and5(8456), 16687353, "Your function is not returning the correct result using our tests values.");'

Challenge Seed

function multiplesOf3and5(number) {
  // Good luck!
  return true;
}

multiplesOf3and5(1000);

Solution

// solution required