6.5 KiB
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
5a23c84252665b21eecc8024 | 州名のパズル | 5 | 302323 | state-name-puzzle |
--description--
このタスクは、Mark Nelson 氏 の DDJ コラム「Wordplay (言葉遊び)」と、NPR 週末版の Will Shortz 氏の週ごとのパズルチャレンジの 1 つ[1] にインスパイアされたもので、もとは David Edelheit 氏の発案によるものです。 チャレンジの内容は、アメリカの州の名前を 2 つ選び、すべての文字を混ぜて並べ替え、 別の 2 つの州の名前を作成するというものでした。(つまり、4 つの州の名前がすべて異なるようにします。) これらの州名は何でしょうか? この問題は Unicon Discussion Web で再び出題され、幾つかの解答が解説付きで紹介されています。 いくつかの役立つと思われるテクニックがあります。Gödel numbering、equivalence relations、equivalence classes などを参考にすると良いでしょう。 これらの基本的なメリットは、Unicon Discussion Web で説明されています。 架空の新しい州のセットを使用する形式で、第 2 のチャレンジも出題されています。
--instructions--
与えられた州名の配列で、この課題を解く関数を記述してください。 この関数は配列を返す必要があります。 各要素はこの形式 ({"from":[],"to":[]}
) のオブジェクトでなければなりません。 "from" 配列には元の名前を含め、"to" 配列には結果として生じる名前を含める必要があります。
--hints--
solve
は関数とします。
assert(typeof solve == 'function');
solve(["New Mexico", "New York", "North Carolina ", "North Dakota", "Ohio", "Oklahoma", "Oregon", "Pennsylvania", "Rhode Island", "South Carolina", "South Dakota"])
は配列を返す必要があります。
assert(
Array.isArray(
solve([
'New Mexico',
'New York',
'North Carolina ',
'North Dakota',
'Ohio',
'Oklahoma',
'Oregon',
'Pennsylvania',
'Rhode Island',
'South Carolina',
'South Dakota'
])
)
);
solve(["New Mexico", "New York", "North Carolina ", "North Dakota", "Ohio", "Oklahoma", "Oregon", "Pennsylvania", "Rhode Island", "South Carolina", "South Dakota"])
は [{ from: ["North Carolina ", "South Dakota"], to: ["North Dakota", "South Carolina"] }]
を返す必要があります。
assert.deepEqual(
solve([
'New Mexico',
'New York',
'North Carolina ',
'North Dakota',
'Ohio',
'Oklahoma',
'Oregon',
'Pennsylvania',
'Rhode Island',
'South Carolina',
'South Dakota'
]),
[
{
from: ['North Carolina ', 'South Dakota'],
to: ['North Dakota', 'South Carolina']
}
]
);
solve(["New York", "New Kory", "Wen Kory", "York New", "Kory New", "New Kory"])
は [{ from: ["New Kory", "New York"], to: ["Wen Kory", "York New"] }, { from: ["New Kory", "New York"], to: ["Kory New", "Wen Kory"] }, { from: ["New Kory", "New York"], to: ["Kory New", "York New"] }, { from: ["New York", "Wen Kory"], to: ["New Kory", "York New"] }, { from: ["New York", "Wen Kory"], to: ["Kory New", "New Kory"] }, { from: ["New York", "Wen Kory"], to: ["Kory New", "York New"] }, { from: ["New York", "York New"], to: ["New Kory", "Wen Kory"] }, { from: ["New York", "York New"], to: ["Kory New", "New Kory"] }, { from: ["New York", "York New"], to: ["Kory New", "Wen Kory"] }, { from: ["Kory New", "New York"], to: ["New Kory", "Wen Kory"] }, { from: ["Kory New", "New York"], to: ["New Kory", "York New"] }, { from: ["Kory New", "New York"], to: ["Wen Kory", "York New"] }, { from: ["New Kory", "Wen Kory"], to: ["Kory New", "York New"] }, { from: ["New Kory", "York New"], to: ["Kory New", "Wen Kory"] }, { from: ["Kory New", "New Kory"], to: ["Wen Kory", "York New"] }]
を返す必要があります。
assert.deepEqual(
solve([
'New York',
'New Kory',
'Wen Kory',
'York New',
'Kory New',
'New Kory'
]),
[
{ from: ['New Kory', 'New York'], to: ['Wen Kory', 'York New'] },
{ from: ['New Kory', 'New York'], to: ['Kory New', 'Wen Kory'] },
{ from: ['New Kory', 'New York'], to: ['Kory New', 'York New'] },
{ from: ['New York', 'Wen Kory'], to: ['New Kory', 'York New'] },
{ from: ['New York', 'Wen Kory'], to: ['Kory New', 'New Kory'] },
{ from: ['New York', 'Wen Kory'], to: ['Kory New', 'York New'] },
{ from: ['New York', 'York New'], to: ['New Kory', 'Wen Kory'] },
{ from: ['New York', 'York New'], to: ['Kory New', 'New Kory'] },
{ from: ['New York', 'York New'], to: ['Kory New', 'Wen Kory'] },
{ from: ['Kory New', 'New York'], to: ['New Kory', 'Wen Kory'] },
{ from: ['Kory New', 'New York'], to: ['New Kory', 'York New'] },
{ from: ['Kory New', 'New York'], to: ['Wen Kory', 'York New'] },
{ from: ['New Kory', 'Wen Kory'], to: ['Kory New', 'York New'] },
{ from: ['New Kory', 'York New'], to: ['Kory New', 'Wen Kory'] },
{ from: ['Kory New', 'New Kory'], to: ['Wen Kory', 'York New'] }
]
);
--seed--
--seed-contents--
function solve(input) {
}
--solutions--
function solve(input) {
var orig = {};
input.forEach(function(e) {
orig[__helpers.removeWhiteSpace(e).toLowerCase()] = e;
});
input = Object.keys(orig);
var map = {};
for (var i = 0; i < input.length - 1; i++) {
var pair0 = input[i];
for (var j = i + 1; j < input.length; j++) {
var pair = [pair0, input[j]];
var s = pair0 + pair[1];
var key = s.split('').sort();
var val = map[key] ? map[key] : [];
val.push(pair);
map[key] = val;
}
}
var result = [];
Object.keys(map).forEach(key => {
for (var i = 0; i < map[key].length - 1; i++) {
var a = map[key][i];
for (var j = i + 1; j < map[key].length; j++) {
var b = map[key][j];
if (new Set([a[0], b[0], a[1], b[1]]).size < 4) continue;
var from = [orig[a[0]], orig[a[1]]].sort();
var to = [orig[b[0]], orig[b[1]]].sort();
result.push({
from,
to
});
}
}
});
return result;
}