1.2 KiB
1.2 KiB
| title |
|---|
| Relationships between * and args |
Presence of * in function definition
# How does *args work in a function definition
def hardFunc(arg1, arg2):
# create a tuple and pollute it with arguments passed to hardFunc
args=(arg1, arg2)
# print out results
print(args[0])
print(args[1])
hardFunc('hard_one', 'hard_two')
# output — Try it yourself now and in sequential snippets!
def softFunc(*args):
# at this point after calling softFunc a tuple with a name of a word
# followed by * is created automatically (in this case the name is args)
# print out results
print(args[0])
print(args[1])
softFunc('soft_one', 'soft_two')
# Now try to do something illegal
hardFunc('one', 'two', 'three')
# Now do things legally
softFunc('one', 'two', 'three')
# or even
softFunc('one', 'two', 'three', 'infinity')
# softFunc handles arbitrary amount of arguments easily by virtue of * syntax
# So using a single variable name in conjuction with * we gained the ability
# to invoke a function with arbitrary amount of arguments.
# Once again when softFunc is called the newly args
# tuple filled with provided arguments is created
# Conclusion softFunc is a more flexible/dynamic verson of a hardFunc