1.8 KiB
1.8 KiB
id | challengeType | title | videoUrl | localeTitle |
---|---|---|---|---|
5900f3801000cf542c50fe93 | 5 | Problem 20: Factorial digit sum | Problema 20: soma do dígito fatorial |
Description
e a soma dos dígitos no número 10! é 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27. Encontre a soma dos dígitos n !
Instructions
Tests
tests:
- text: <code>sumFactorialDigits(10)</code> deve retornar 27.
testString: 'assert.strictEqual(sumFactorialDigits(10), 27, "<code>sumFactorialDigits(10)</code> should return 27.");'
- text: <code>sumFactorialDigits(25)</code> deve retornar 72.
testString: 'assert.strictEqual(sumFactorialDigits(25), 72, "<code>sumFactorialDigits(25)</code> should return 72.");'
- text: <code>sumFactorialDigits(50)</code> deve retornar 216.
testString: 'assert.strictEqual(sumFactorialDigits(50), 216, "<code>sumFactorialDigits(50)</code> should return 216.");'
- text: <code>sumFactorialDigits(75)</code> deve retornar 432.
testString: 'assert.strictEqual(sumFactorialDigits(75), 432, "<code>sumFactorialDigits(75)</code> should return 432.");'
- text: <code>sumFactorialDigits(100)</code> deve retornar 648.
testString: 'assert.strictEqual(sumFactorialDigits(100), 648, "<code>sumFactorialDigits(100)</code> should return 648.");'
Challenge Seed
function sumFactorialDigits(n) {
// Good luck!
return n;
}
sumFactorialDigits(100);
Solution
// solution required