45 lines
1006 B
Markdown
45 lines
1006 B
Markdown
---
|
|
title: Create a Linear Scale with D3
|
|
---
|
|
## Create a Linear Scale with D3
|
|
|
|
In this D3 challenge you are required to change the scale variable to create a linear scale. Then set the output variable to the scale called with an input argument of 50.
|
|
|
|
### Hint 1
|
|
|
|
The syntax for creating a scale is:
|
|
```javascript
|
|
const scale = d3.scaleLinear();
|
|
```
|
|
|
|
### Hint 2
|
|
|
|
The `const` scale is a method, which accepts a value.
|
|
|
|
### Hint 3
|
|
|
|
The scaling factor should be set to `50`.
|
|
|
|
### Hint 4
|
|
|
|
The scaling factor is set like this:
|
|
```javascript
|
|
const output = scale(scalingFactor);
|
|
```
|
|
Where `scalingFactor` is a number.
|
|
|
|
### Solution
|
|
|
|
To solve this challenge, the `scale` variable has to be re-initialized with a D3 scale ans the scaling factor in the output has to be set to `50`, to do this, change you code to look like this:
|
|
```javascript
|
|
<body>
|
|
<script>
|
|
const scale = d3.scaleLinear();
|
|
const output = scale(50);
|
|
d3.select("body")
|
|
.append("h2")
|
|
.text(output);
|
|
</script>
|
|
</body>
|
|
```
|