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id	title	challengeType	forumTopicId	dashedName
5900f3f21000cf542c50ff05	Problem 134: Prime pair connection	5	301762	problem-134-prime-pair-connection

--description--

Consider the consecutive primes p_1 = 19 and p_2 = 23. It can be verified that 1219 is the smallest number such that the last digits are formed by p_1 whilst also being divisible by p_2.

In fact, with the exception of p_1 = 3 and p_2 = 5, for every pair of consecutive primes, p_2 > p_1, there exist values of n for which the last digits are formed by p_1 and n is divisible by p_2. Let S be the smallest of these values of n.

Find \sum{S} for every pair of consecutive primes with 5 ≤ p_1 ≤ 1000000.

--hints--

primePairConnection() should return 18613426663617120.

assert.strictEqual(primePairConnection(), 18613426663617120);

--seed--

--seed-contents--

function primePairConnection() {

  return true;
}

primePairConnection();

--solutions--

// solution required

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