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id	title	challengeType	forumTopicId	dashedName
5900f3d01000cf542c50fee3	Problem 100: Arranged probability	5	301724	problem-100-arranged-probability

--description--

If a box contains twenty-one colored discs, composed of fifteen blue discs and six red discs, and two discs were taken at random, it can be seen that the probability of taking two blue discs.

{P(BB)} = \frac{15}{21}×\frac{14}{20} = \frac{1}{2}

The next such arrangement, for which there is exactly a 50% chance of taking two blue discs at random, is a box containing eighty-five blue discs and thirty-five red discs.

By finding the first arrangement to contain over limit discs in total, determine the number of blue discs that the box would contain.

--hints--

arrangedProbability(20) should return a number.

assert(typeof arrangedProbability(10) === 'number');

arrangedProbability(20) should return 15.

assert.strictEqual(arrangedProbability(20), 15);

arrangedProbability(100) should return 85.

assert.strictEqual(arrangedProbability(100), 85);

arrangedProbability(100000) should return 97513.

assert.strictEqual(arrangedProbability(100000), 97513);

arrangedProbability(1000000000) should return 3822685023.

assert.strictEqual(arrangedProbability(1000000000), 3822685023);

arrangedProbability(1000000000000) should return 756872327473.

assert.strictEqual(arrangedProbability(1000000000000), 756872327473);

--seed--

--seed-contents--

function arrangedProbability(limit) {

  return true;
}

arrangedProbability(20);

--solutions--

function arrangedProbability(limit) {
  // Based on https://www.mathblog.dk/project-euler-100-blue-discs-two-blue/
  let blue = 15;
  let discs = 21;

  while (discs < limit) {
    const nextBlue = 3 * blue + 2 * discs - 2;
    const nextDiscs = 4 * blue + 3 * discs - 3;

    blue = nextBlue;
    discs = nextDiscs;
  }
  return blue;
}

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