1.5 KiB
1.5 KiB
id | challengeType | videoUrl | localeTitle |
---|---|---|---|
5900f3761000cf542c50fe88 | 5 | 问题9:特殊的毕达哥拉斯三重奏 |
Description
a 2 + b 2 = c 2
例如,3 2 + 4 2 = 9 + 16 = 25 = 5 2 。恰好存在一个毕达哥拉斯三元组,其中a + b + c = 1000.求产品abc使得a + b + c = n
。 Instructions
Tests
tests:
- text: <code>specialPythagoreanTriplet(1000)</code>应返回31875000。
testString: assert.strictEqual(specialPythagoreanTriplet(1000), 31875000);
- text: <code>specialPythagoreanTriplet(24)</code>应该返回480。
testString: assert.strictEqual(specialPythagoreanTriplet(24), 480);
- text: <code>specialPythagoreanTriplet(120)</code>应该返回49920。
testString: assert([49920, 55080, 60000].includes(specialPythagoreanTriplet(120)));
Challenge Seed
function specialPythagoreanTriplet(n) {
let sumOfabc = n;
// Good luck!
return true;
}
specialPythagoreanTriplet(1000);
Solution
// solution required
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